Page 175 - Maths Skills - 7
P. 175

The Triangle and Its Properties                                                                        173

        Let us learn more through examples.


              Let’s Attempt
                                                                                                         A
        Example 1:  In Fig., D is a point on the side BC of DABC. Prove that, AC + AB + BC > 2AD.
        Solution:      Using triangle inequality property in Ds ADC and ADB, we have
                       AC + CD > AD                          …(i)
                       AB + DB > AD                         …(ii)                                   C    D         B

                       Adding (i) and (ii) on both the sides, we get
                       AC + CD + AB + DB > AD + AD
                       or  AC + (CD + DB) + AB > 2AD                                             [Q CD + DB = BC]
                       or  AC + BC + AB > 2AD

                       Thus, AC + AB + BC > 2AD (proved).

        Example 2:  Can triangles be drawn with sides measuring:
                       (i)  1.5 cm, 3.5 cm, 6 cm                      (ii)  3 cm, 4 cm, 5 cm
        Solution:      (i)  Clearly, 1.5 + 3.5 = 5 < 6

                             Since the sum of two of these sides is not greater than the third side, so the triangle cannot
                           be drawn.

                       (ii)  Clearly, 3 + 4 = 7 > 5;
                            4 + 5 = 9 > 3 and 5 + 3 = 8 > 4

                            Since the sum of two of these sides is greater than the third side, so the triangle can be drawn.



                                                   Exercise 10.2


          1.  In Fig., D is a point on the side AC of DABC.

            Fill in the blanks with > or < or = :
             (i)  BD ......... AB + AD                        (ii)  BC + CD......... BD
                           1
            (iii)  BD .........   (AB + BC + AC)
                           2
          2.  In Fig., P and Q are the points on the side BC of DABC and AP = AQ.
            Prove that  AC + AB + BC > 2AP – PQ.
          3.  Which of the following can be the sides of a triangle?

             (i)  1.8 cm, 3.5 cm, 6 cm        (ii)  1 cm, 3 cm, 2 cm          (iii)  1.5 cm, 2.5 cm, 5 cm
            (iv)  5 cm, 7 cm, 12 cm           (v)  8.5 cm, 2 cm, 5 cm         (vi)  3.4 cm, 2.1 cm, 5.3 cm

          4.  Three points A, B, C are collinear and B is the midpoint of A and C as shown
            in Fig. Can you draw a triangle ABC?

          5.  In Fig., is
             (i)  OA + OB > AB?               (ii)  OA + OC = AC?
            (iii)  OB + OC < BC?
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