Page 83 - Maths Skill - 3
P. 83

Division                                                                                                81


              Let’s Attempt


        Example 1:   Divide 421 by 5 and write the divisor, quotient and remainder.


        Solution:        Step 1:    Start at hundreds place. Since 4 < 5, the division is not possible.
                                     Regroup 4 hundreds as 40 tens and add it to 2 tens at tens place.
                                     Now, we have 42 tens as the dividend. Since 42 > 5. Division is
                                     possible.

                                       42 tens ÷ 5, gives 8 tens as quotient and 2 tens as remainder.
                                     Write the quotient in tens column.


                          Step 2:    Bring down the next digit of dividend. 2 tens and 1 one make
                                     21 ones.

                                     21 > 5, so, the division is possible.                             H T O

                                       21 ones ÷ 5, gives 4 ones as quotient and 1 one                      8   4
                                                                                                        4
                                     as remainder.                                                 5  – 4   2   1
                                                                                                            0
                                     Write the quotient in ones column.                                     2   1

                                     Thus, Quotient = 84 and Remainder = 1                                –2    0

                                                                                                                1




        Example 2:   Divide 27 by 2 and write the              Example 3:  Divide 489 by 4 and write the
                         quotient and remainder.                                quotient and remainder.
                                                               Solution:
        Solution:                 T O                                                    H T O

                                  1    3                                             4    1   2   2
                                                                                          4
                                                                                                  9
                                                                                              8
                              2   2    7                                                – 4
                                – 2                                                       0   8
                                  0    7                                                  –   8
                                  –    6                                                      0   9

                                       1                                                      –   8

                                                                                                  1
                          Quotient = 13

                          Remainder = 1                                          Quotient = 122

                                                                                 Remainder = 1
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