Page 126 - Maths Skill - 6

124 Maths

To do this, we sketch a horizontal line AB after that we construct two perpendicular lines at both ends A
and B. Now cut the line segment equal of AB from both perpendicular lines passing through A and B.

In this way, we will construct a square, now draw AC and BD, there are the diagonals of square and
where these diagonals cut each other, that point of intersection called centre of square.

Step 2: Now, Take compass and put one tip at the point E and mark a cut at one of its diagonal and that cut point
is represented by point F.
Now put the length of EF on the compass and set one tip at E and sketch a circle of given radius EF
around the point E.
In this way a circle (hole) is constructed with in the square and both contain the same centre.

CONSTRUCTION OF RECTANGLE HAVING DIAGONALS DIVIDES OPPOSITE ANGLE INTO 60° AND 30°.
Before doing this, we sketch a rough diagram of it.

D C

30°
60°
A B

Now, Let’s construct this by following the steps given below:
Step 1: First of all, we draw a line AB with end points A and B and after that draw a perpendicular line at B to
the line segment AB with is shown in fig. given below:

A B
Step 2: Now, with the help of protractor, draw an angle of 60° at point A and extend the line of angle 60° towards
the perpendicular line. This arrangement is shown in given fig. below and where these two lines cut each
other, that point is represented by ‘C’.

C

60°
A B