Page 43 - Mathematics Class - XII
P. 43

DEMONSTRATION
            1.  Take one more point M  (1 + 0.8, 0) to the right side of A, where 0.8 is an increment in x = 1.
                                      1
            2.  Draw the perpendicular from M  to meet the curve at N . Coordinates of N  be (1.8, 1.7).
                                              1                      1                 1
            3.  Draw a perpendicular from the point P (1, 1.4) to meet N M  at T .
                                                                      1  1    1
            4.  Reduce the increment in x to 0.6 (0.6  < 0.8) to get another point M  (1 + 0.6, 0) and get the corresponding
                                                                               2
               point N  on the curve.
                       2
            5.  Let the perpendicular PT  intersects N M  at T .
                                       1
                                                    2
                                                            2
                                                       2
            6.  Repeat the above steps for some more points so that  increment in x becomes smaller and smaller.
        OBSERVATION
            1.  From the graph we observe the following:


                  S. No           Increment in x  where x  = 1                Corresponding increment in y   0
                                                 0
                                                           0
                    1                     |Δx | = 0.8                                 |Δy | = 0.3
                                             1
                                                                                         1
                    2                     |Δx | = 0.6                                 |Δy | = 0.22
                                             2                                           2
                    3                     |Δx | = 0.4                                 |Δy | = 0.14
                                             3                                           3
                    4                     |Δx | = 0.2                                 |Δy | = 0.1
                                             4                                           4

                    5                     |Δx | = 0                                   |Δy | = 0
                                             5                                           5


            2.  We see that Δy becomes smaller when Δx becomes smaller.
            3.  Hence, lim y   0    for a continuous function.
                       x 0

        CONCLUSION
        From  the  above  activity,  it  is  verified  that  for  a  function  to  be  continuous  at  any  given  point  x ,
                                                                                                                   0
        Δy = | f (x  + Δ x) – f ( x  )| is arbitrarily small provided Δ x is sufficiently small.
                  0            0

        APPLICATION
        This activity is helpful in explaining the concept of derivative (left hand or right hand) at any point on the
        curve corresponding to a function.


               Knowledge Booster
              Reasons of Discontinuity:
              The discontinuity of a function may be due to the following reasons (It is assumed the function f (x) is defined at x = c)
                1.  The left hand limit or right hand limit or both may not exist.
                2.  The left hand limit or right hand limit exist but are not equal.
                3.  The left hand limit or right hand limit exist and are equal but not equal to f (c).





                                                                                                                41
   38   39   40   41   42   43   44   45   46   47   48