Page 19 - Maths Skill - 3
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4-digit Numbers                                                                                         17

        Example 2:  Find the place value of 5 in 2853.                            Fact-o-meter

        Solution:         Th     H     T    O                                  Place value of zero is always 0.

                           2     8     5     3                                 For example, place value of 0
                                                                               in 1054 = 0 × 100 = 0
                         5 is at tens place, so its place value is 50.




                                                   Exercise 2.3


          1. Write the place value and face value of each digit in the following numbers.

                (a) Th H         T    O         Place   Face    (b)  Th H          T    O        Place   Face
                       7    0    5    1         value   value           6     2    3    3        value    value












          2. Write the place value of the encircled digits.
                (a)     3      5      6      3                     (b)      6      9      4      5

                (c)     1      3      8      9                     (d)      2      9      3      0

                (e)     3      4      1      3                     (f)      3      8      0      5

        Expanded Form

        When we write a number in terms of sum of the place values of its digits, it is called the
        expanded form of that number.

        For example, 2617 is made up of 2 thousands, 6 hundreds, 1 ten and 7 ones.
        Thus, the expanded form of 2617 is :

        2617 = 2 thousands + 6 hundreds + 1 ten + 7 ones                 or

        2617 = 2000 + 600 + 10 + 7
        If we reverse this process, we can get the standard form (short form) of the numbers.

        Thus, the short form of 2000 + 600 + 10 + 7 = 2617.


              Let’s Attempt


        Example 1:  Write the following numbers in expanded form.
                          (a) 3752                         (b) 6083

        Solution:        (a) Expanded form of 3752 = 3000 + 700 + 50 + 2
                         (b) Expanded form of 6083 = 6000 + 0 + 80 + 3
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