Page 40 - Chemistry - XI
P. 40

Valency                           Molecularweight
                                Salt            Mol. Wt.                   Equivalentwt. =
                                                              of Metal                        Total valency of metal



                       Potassium carbonate         138            2                        138  =  69 0.
                                                                                            2


                       Potassium bicarbonate       100            1                        100  = 100 0.
                                                                                            1


                       Sodium carbonate            106            2                        106  =  53 0.
                                                                                            2


                 (iv)  Equivalent weight of an oxidising or reducing agent:

                                                                                 Molecularmassoffthe substance
                        Equivalent weight of an oxidising /reducingagent =
                                                                               Number of electrons gained /lostby
                                                                               one molecule in thhe redox reaction

                                      Equivalent weights of common oxidising and reducing agents
                                                                                                 Number of
                                                                                                  electrons          M
                          Oxidising or                           Molecular      Ion-electron     gained or   Eq.wt. =  n
                        Reducing Agent           Formula          mass (M)        equation        lost per
                                                                                                  molecule
                                                                                                    (n)



                       Potassium          KMnO                      158      MnO    8 H    e 5       5      158
                                                                                 4
                       permanganate             4                                  2                          5  =  31 6.
                                                                               Mn
                                                                                      4
                                                                                        HO
                                                                                         2
                       Mohr’s salt
                                                                                        3+
                                                                                 2+
                       Ferrous ammonium   FeSO .(NH ) SO .6H O      392       Fe → Fe  + e  –        1      392  = 392
                                                             2
                                                    4 2
                                               4
                                                         4
                       sulphate (hydrated)                                                                    1
                       Ferrous sulphate                                          2+     3+  –               152
                       (anhydrous)        FeSO 4                    152       Fe → Fe  + e           1        1  = 152
                       Crystalline ferrous   FeSO .7H O             278       Fe → Fe  + e  –        1       278
                                                                                        3+
                                                                                 2+
                       sulphate (hydrated)     4   2                                                             =  278
                                                                                                              1
                       Oxalic acid        COOH                                  2                           90
                       (anhydrous)        | COOH                     90     CO  4     2 CO    e 2    2       2  =  45
                                                                                         2
                                                                              2
                       Crystalline oxalic  COOH                     126         2                    2      126
                       acid (hydrated)    | COOH .2 HO                      CO  4     2 CO    e 2             2  =  63
                                                    2
                                                                                         2
                                                                              2
              11. Primary standard is a substance whose standard solution can be prepared by dissolving an accurately
                  weighted amount of it in water and making up the solution to a known volume by dilution with water.
                  weighted amount of it in water and making up the solution to a known volume by dilution with water.
                  A primary standard should fulfi l the following requirements:
                  A primary standard should fulfi l the following requirements:
                  (i)  It should be easily available in highly pure state.
                  (i)  It should be easily available in highly pure state.
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