Page 107 - Maths Skills - 8
P. 107

Linear Equations in One Variable                                                                       105

                       ⇒  x + 23 = 2x – 30

                       ⇒  x – 2x = – 30 – 23
                       ⇒  – x = – 53                        Hence, present age of Rajesh = x + 8 = 53 + 8 = 61 years,
                       ⇒  x = 53                            and present age of Sailesh = x = 53 years.


        Example 9:  A steamer in downstream covers the distance between two ports in 3 hours while it covers the same
                       distance upstream in 4 hours. If the speed of  the  stream is 2 km/h. Find the speed of the steamer
                       in still water. Check your solution.

        Solution:      Let the speed of steamer in still water be x km/h.
                       Speed upstream = (x – 2) km/h
                       Speed downstream = (x + 2) km/h           Physical Quantity      Upstream      Downstream

                       Distance between two points
                                4(x – 2) km = 3(x + 2) km              Speed           (x – 2) km/h    (x + 2) km/h
                                      4x – 8 = 3x + 6                  Time                4 h             3 h

                                           x = 14              Distance = speed × time  4(x – 2) km    3(x + 2) km

                         Hence, the speed of steamer in still water is 14 km/h.

        Example 10:  The length of a rectangle is 6 units more than its breadth. Its perimeter is 20 units. Find its length
                       and breadth.
        Solution:      It is given that the length of a rectangle is 6 units more than its breadth and its perimeter is 20 units.
                       Let the breadth of the rectangle be x units. Then, the length of the rectangle will be (x + 6) units.

                       According to the given condition:
                       Perimeter = 20 units
                       ⇒  2[length + breadth] = 20

                       ⇒  2[(x + 6) + x] = 20
                       ⇒  2(2x + 6) = 20
                       ⇒  4x + 12 = 20                               ∴  x = 2 units
                       ⇒  4x = 20 – 12 = 8                               Therefore, length = x + 6 = 2 + 6 = 8 units,
                                                                         and breadth = x = 2 units.
                       ⇒ x =   8  = 2

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        Example 11:  Two trains start simultaneously from two stations 300 km apart and move towards each other on
                       parallel tracks. The speed of one train is 22 km/h more than the speed of the other. If the distance
                       between the two trains after 2 hours is 20 km, find the speed of each train.
                                                                                      [Hints: Distance = speed × time]
        Solution:      It is given that the distance between the two stations is 300 km, and the speed of the first train is
                       22 km/h more than the speed of the second train. Also the distance between the two trains after
                       2 hours is 20 km. Let the speed of the second train be x km/h. Then, the speed of the first train will
                       be (x + 22) km/h. Distance covered by the first train in 2 hours = 2 × (x + 22) km. Distance covered
                       by the second train in 2 hours = 2 × x km.
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