Page 125 - Maths Skills - 8
P. 125

Comparing Quantities                                                                                   123

        Example 2:  What will be the amount on ` 10020 for 2 years when the interest is compounded annually at the
                       rate of 10% per annum for the first year and 15% for the second year.
        Solution:      Given: P = ` 10020        n = 2 years        R  = 10%        R  = 15%        A = ?
                                                               1             2
                       Amount (A) after 2 years
                                R        R                    10        15
                       = P 1     1     1   2    = ` 10020   1        1

                               100       100                  100      100
                                   110    115
                       = ` 10020               = ` 10020 (1.10) (1.15) = ` 12675.30.
                                   100    100

        Example 3:  Find the compound interest on ` 12000 at 20% per annum for 2     1  years.
                                                                                      4
        Solution:      Given: P = ` 12000                          R = 20%
                             1                      x   1
                       T = 2   years, here n = 2 and   =           A = ?
                              4                     y     4
                                                                     x  R                             1    20

                                                               n


                                          1
                       Amount (A) after 2  years = P  1    R         1   y     = ` 12000  1   20   2    1   4




                                          4               100        100                  100          100


                                       2
                                   120     105               12 12     21
                       = ` 12000                = `   12000                = ` 18144
                                    100     100              10 10     20
                       Compound interest = ` (18144 – 12000) = ` 6144.
                                                    Exercise 8.5


          1.  By using formula, find out the amount and the compound interest.

             (i)  Principal = ` 24000, Rate = 5% per annum, Time = 3 years.
            (ii)  Principal = ` 8000, Rate = 12% per annum, Time = 2 years.
                                                                     1
            (iii)  Principal = ` 18000, Rate = 10% per annum, Time = 3  years.
                                                                     2
          2.  Shyam purchased a car for ` 180000 by taking a loan from a bank. If the bank takes interest 10% for
            the first year and 12% for the second year, then find the total compound interest paid by him to the
            bank at the end of the second year.
          3.  Find the compound interest on ` 46875 at 8% per annum for 2   1  years.
                                                                            2
          4.  Manohar borrowed ` 10000 from his friend 2 years ago. If his friend takes 8% per annum compound
            interest, then find the interest on the principal.
          5.  Find the amount and the compound interest on ` 24500 for 3 years, compounded annually, rate of
            interest being 5%, 8% and 10% per annum for the first, second and third year respectively.
          6.  Find the amount and the compound interest on ` 18000 for 2 years, compounded annually, the rate of
            interest being 8% for first year and 12% for second year.
                                                      1
          7.  Ram deposited ` 781250 in a bank for 3  years. If the bank pays 8% per annum compound interest,
                                                      2
            then find the total amount he received.
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