Page 127 - Maths Skills - 8
P. 127

Comparing Quantities                                                                                   125



                                                    Exercise 8.6


          1.  Find the amount and the compound interest on ` 18000 for 2 years at 8% per annum, compounded
            half-yearly.
          2.  Find the amount and the compound interest on ` 10000 for 3 years at 12% per annum, compounded half-
            yearly.

          3.  Find the compound interest on ` 31250 for 9 months, at 16% per annum compounded quarterly.
          4.  What will be the compound interest on ` 15000 for 1 year at 4% per annum compounded quarterly?

        GROWTH (APPRECIATION) AND DEPRECIATION
        Growth means increase counted as increase in size, amount or degree of anything over a period of time. For
        example, the growth of height and weight of a child, the growth of a tree, the growth of population density etc.

        The decrease in value of an article over a period of time is called depreciation. For example, the value of a
        machine decreases over a period of time due to its wear and tear.

        Following formulae are used in growth and depreciation problems:
        Rule 1:  When growth takes place at a constant rate
                 Let P = Initial value, R = Rate of growth and n = Time of growth in years.
                                                                                                            R    n
                 Then, for constant growth, the final value of growth (A) after n years is given by    A= P  1

                                                                                                           100
                                             R    n  
                                          
                 Net growth = A – P = P  1+         − 1
                                             100   
                                                       
        Rule 2:  When rate of growth is different for every year
                 Let, P = initial value and R , R , R , ... be the rates of growth for the first year, second year, third year and
                                           1
                                                 3
                                              2
                 so on.


                 Then, the final value of growth (A) is given by:  A= P  1+  R     1+  R     1+  R    ... 1+  R   .
                                                                                                             n

                                                                                       2

                                                                             1



                                                                                                 3

                                                                           100      100        100         100
        Rule 3:  When depreciation takes place at a constant rate
                 When depreciation takes place at a constant rate, then we use (– R) in the place of R in the growth
                 formula.                                                         n

                 In case of depreciation, final value (A) is given by  A= P  1   R


                                                                             100
        Rule 4:  When depreciation rate is different for every year
                 When depreciation rate is R  for the first year and R  for the second year, then final value (A) is given by
                                            1                     2
                                 
                        
                                          
                             R
                                       R
                  A= P  1−  100  1− 100 , , where P = initial value.
                                        2
                               1
                                 
                        
                                          
                        
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