Page 126 - Maths Skills - 8
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124                                                                                                  Maths

        SOME ADDITIONAL CASES

        Rule 1:  When Interest is Compounded Half-Yearly
                 Let Principal = ` P, Rate = R% annually, and Time = n years.
                                                                        R
                 When interest is compounded half-yearly, then rate =      % and Time = (2n) half-years.
                                                                        2
                                                  R/ 2   2n
                 Therefore, Amount (A) = P  1               and  C.I. = A – P.

                                                  100

        Rule 2:  When Interest is Compounded Quarterly
                 Let Principal = ` P, Rate = R% per annum, and Time = n years.

                                                                      R
                 When interest is compounded quarterly, then rate =      % and time = 4n quarters.
                                                                      4


                 Therefore, A= P  1     R/  4     4n  and C.I. = A – P.

                                        100



              Let’s Attempt


        Example 1:  Find the compound interest on ` 20000 for 2 years at 20% per annum when compounded half-
                       yearly.
        Solution:      Given: P = ` 20000                        R = 20% per annum, compounded half-yearly
                       n = 2 years                               A = ?

                                                        R/  2   2n              10   4            110   4
                       Amount (A) after 2 years = P  1         = ` 20000    1         = ` 20000

                                                         100                   100                  100
                                    11 11 11 11
                       = `  20000                      = ` 29282

                                    10 10 10 10
                       Compound interest = ` (29282 – 20000) = ` 9282.
        Example 2:  Find out the compound interest on ` 10000 for 6 months at 8% per annum compounded quarterly.

        Solution:      Given: P = ` 10000                                        R = 8%, compounded quarterly

                                       6         1
                       n = 6 months =     year =   year                          A = ?
                                      12          2
                                                          R/  4   4n              8/ 4   4   1 2           2   2
                       Amount (A) after 6 months = P   1           = ` 10000   1           = ` 10000   1
                                                           100                    100                     100

                                   102   2            102    02
                       = ` 10000        = ` 10000                 = ` 10404

                                    100               100 100
                       ∴  Compound interest = ` (10404 – 10000) = ` 404.
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