Page 155 - Maths Skills - 7
P. 155

Lines and Angles                                                                                       153

        The vertically opposite angles are always equal to each other.

        In Fig. two lines AB and CD intersect each other at a point O.
        As a result of this intersection, four angles ∠1, ∠2, ∠3 and ∠4 are formed. ∠1 and ∠3 form a pair of vertically
        opposite angles. ∠2 and ∠4 form another pair of vertically opposite angles. Therefore, ∠1 = ∠3 and ∠2 = ∠4.


             Absorbing Facts

          Angles at a Point                                                                     D     C
          When different rays start from a common vertex or initial point, they form different      3  2   B
          angles. These angles are called angles at a point.                                      4     1
          In Fig., we find that, ∠1 + ∠2 + ∠3 + ∠4 + ∠5 = 360°.                                      5      A
          Thus, the sum of all angles at a point is always 360°.                                       O
                                                                                                E



               Let’s Attempt

        Example 1:  Find the complement of the following angles.

                       (i)  47°                                       (ii)  55°
        Solution:      We know that the sum of the measure of an angle and its complement is 90°.

                       (i)  Complement of 47° = 90° – 47° = 43°.      (ii)  Complement of 55° = 90° – 55° = 35°.

        Example 2:  Find the supplement of the following angles.
                       (i)  76°                                       (ii)  115°

        Solution:      We know that the sum of the measure of an angle and its supplement is 180°.
                       (i)  Supplement of 76° = 180° – 76° = 104°.    (ii)  Supplement of 115° = 180° – 115° = 65°.

        Example 3:  Find the value of x in Fig. 1 and 2.

                                                                                          Q
                       (i)              B                             (ii)
                                                                                   4x
                                                                                 O    x
                                  4x    2x                                  R   2x   3x      P

                             C      O         A
                                   Fig. 1                                          S
                                                                                     Fig. 2


        Solution:      (i)       ∠AOB + ∠BOC  = 180°             (ii)     ∠POQ + ∠QOR + ∠ROS + ∠SOP  = 360°

                                                         [Linear pair]                                                   [Angles at a point]

                            ⇒             2x + 4x  = 180°             ⇒                     x + 4x + 2x + 3x  = 360°

                            ⇒                  6x  = 180°             ⇒                                 10x  = 360°

                            ⇒                   x  = 30°              ⇒                                    x  = 36°


                            Hence, the value of x is 30°.             Hence, the value of x is 36°.
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