Page 63 - Mathematics Class - XII
P. 63

OBSERVATION

            1.  V  = Volume of the open box (when x = 1.5) = 396 cm 3
                 1
            2.  V  = Volume of the open box (when x = 2.1) = 471.74 cm 3
                 2
            3.  V  = Volume of the open box (when x = 2.7) = 508.03 cm 3
                 3
            4.  V = Volume of the open box (when x = 3) = 513 cm 3

            5.  V  = Volume of the open box (when x = 3.5) = 504 cm 3
                 4
            6.  V  = Volume of the open box (when x = 4.1) = 468.38 cm 3
                 5
            7.  Volume V  is less than volume V.
                         1
            8.  Volume V  is less than volume V.
                         2
            9.  Volume V  is less than volume V.
                         3
           10.  Volume V  is less than volume V.
                         4
           11.  Volume V  is less than volume V.
                         5
        Hence, volume of the open box is maximum when x = 3.



        CONCLUSION
        From this activity we learn that an open box of maximum volume from a rectangular sheet by cutting equal square
        from each corner, can be formed.


        APPLICATION
        This activity is useful in explaining the concepts of maxima/minima of function.


                             Knowledge Booster

                             We can also check volume of given box is maximum when x = 3, by using calculus.
                             Volume of the given box:
                                             V  = (25 – 2x) × (15 – 2x) × x
                                                 = 4x – 80x  + 375x, 0 < x < 7.5
                                                    3
                                                         2
                                            dV
                             Now,                = 12x  – 160x + 375
                                                     2
                                            dx
                                            dV
                                        Put      = 0
                                            dx
                             ⇒  12x  – 160x + 375  = 0
                                   2
                             ⇒                x  = 10.3 or x = 3.03
                             ⇒                x  = 3 (approx) as 0 < x < 7.5
                                            2
                                           d V
                             Also,         dx 2   = 24x – 160

                                         d V      24 3 160        72 160       88 0
                                          2
                                          dx 2

                                              x 3
                             Hence, volume should be maximum at x = 3.03 or 3 (approx.).

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