Page 20 - Mathematics Class - XII
P. 20

Viva-Voce



            1.  Is function f defined by f = {(1, 2), (3, 4), (5, 6), (8, 6), (10, –1)} a one to one function?
          Ans.  Here, two different values in the domain, 5 and 8, have the same output 6, hence function f is not a one to
               one function.
            2.  If X = {1, 2, 3}, Y = {1, 4, 9} and f = {(1, 1), (2, 4), (3, 9)} is a function from X to Y. Is this function
               one-one onto?
          Ans.  Here, every element of X has a distinct image in Y and each element of Y has distinct pre-image in X, so
               function f is one-one onto.
            3.  Find the total number of onto functions (surjective functions) from set X = {1, 2, 3, 4} to set Y = {a, b, c}.
          Ans.  If X has m elements and Y has n elements, the number of onto functions are,
               n  –  C (n – 1)  +  C (n – 2) ...(–1) n – 1 n  n – 1 (1) ]
                                                    [ C
                                                             m
                                 n
                                          m
                             m
                 m
                    n
                      1
                                   2
                Here, m = 4 and n = 3,
                So, the number of onto functions is: 3 –  C (2) +  C 1 = 36.
                                                            4
                                                               3
                                                                    4
                                                       3
                                                    4
                                                         1        2
            4.  If X = {a, b, c, d}, Y = {x, y, z} and function f = {(a, z), (b, y), (c, z) and (d, z)}, what type of function is this?
          Ans.  Here, element x of Y has no pre-image in X. And a, c, d of X has same image z in Y. So, this function is
               neither injective nor surjective, i.e., neither one-one nor onto.
            5.  If : A → B is a bijective function, such that n (A) = 12, then n (B) = ?
          Ans.  We know that a bijective function is one-one onto function.
                So, range of  f = Co domain of f
                   ∴ n (A) = n (B) = 12.
                                                          MCQs



          1.  If function f : R → R defined by f (x) = e , then f will be
                                                     x
              a)  one-one but not onto                        b)  one-one and onto
              c)  Neither one-one nor onto                    d)  None of these

          2.  Let f : R → R be defined as f (x) = x  + 4, choose the correct answer
                                                2
              a)  one-one but not onto                        b)  one-one onto
              c)  Neither one-one nor onto                    d)  None of these
          3.  Function f : N → N defined by f (x) = 7x + 11 is
              a)  one-one function                            b)  many-one function
              c)  one-one into function                       d)  many-one onto function
          4.  Which of the following functions are one-one onto if f : z → z?
              a)  f (x) = x 3         b)  f (x) = x +2        c)  f (x) = 2x + 1     d)  f (x) = x  + 1
                                                                                                2
          5.  Function f : N → N defined by f (x) = 2x is
              a)  one-one and onto    b)  one-one but not onto   c)  Neither one-one nor onto     d)  None of these

        Answers:   1. a) one-one but not onto             2. b) one-one onto               3. a) one-one function
                    4. b)  f (x) = x +2                   5. b) one-one but not onto

          18
   15   16   17   18   19   20   21   22   23   24   25