Page 40 - Revised Maths Wisdom Class - 6
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38                                                                                                  MATHS


        Example 3:  Is 31 a factor of 7320?                     Example 4:  Is 3551 a multiple of 53?
        Solution:      To check whether 31 is a factor of 7320,   Solution:   The multiple of a number is exactly
                       we divide it by 31. If the remainder is                divisible by that number. So we divide

                       zero, it is a factor otherwise not.                    3551  by  53  to  check  whether  the
                           236                                                remainder is 0 or not.
                       31  7320                                                    67
                           62                                                  53  3551
                           112                                                     318
                             93                                                      371
                             190                                                     371
                             186                                                       0
                                 4
                                                                              The remainder  is 0. So, 3551 is a
                       Since, the remainder is 4, so 31 is not a              multiple of 53.
                       factor of 7320.

        Example 5:  The product of two numbers is 42. Their sum is 17. What are the numbers?

        Solution:      Since, the product of the two numbers is 42, let’s write the factors of 42 first:
                       42  = 1 × 42

                             2 × 21
                             3 × 14

                             6 × 7
                       Here, 3 + 14 = 17 so the required numbers are 3 and 14.

        Perfect Numbers
        A number for which sum of all its factors is equal to twice the number is called a perfect number. For example,
        6, 28 and 496 are perfect numbers because
          ●  Factors of 6 are 1, 2, 3 and 6                   ●  Factors of 28 are 1, 2, 4, 7, 14 and 28
            Sum of factors = 1 + 2 + 3 + 6 = 12 = 2 × 6         Sum of factors = 1 + 2 + 4 + 7 + 14 + 28 = 56 = 2 × 28
            Thus 6 is a perfect number.                         Thus, 28 is a perfect number.
                                                                Now, verify whether 496 is a perfect number.

        Common Factors
            Factors that are common to two or more numbers are said to be common factors. For example, factors of 15
            are  1 , 3,  5 , 15
            Factors of 20 are  1 , 2,  5 , 4, 10 and 20

            Common factors of 15 and 20 are 1 and 5.
        Common Multiples

            Multiples that are common to two or more numbers are said to be common multiples. For example,
            Multiples of 3 are 3, 6, 9,  12 , 15, 18, 21,  24 , ...

            Multiples of 4 are 4, 8,  12 , 16, 20,  24 , 28, ...
            Common multiples of 3 and 4 are 12 and 24.
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