Page 78 - Maths Skills - 8
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76                                                                                                  Maths

        Example 2:  Find the value of (5x y) × (– 4xy ), when x = 2 and y = – 5.
                                           2
                                                      2
        Solution:      (5x y) × (– 4xy ) = {5 × 2  × (– 5)} × {(– 4) × 2 × (– 5) }
                                     2
                                                                           2
                                               2
                          2
                                       = (– 100) × (– 200) = 20000
        Example 3:  Multiply  −   7  xy  by  10  xy  and verify your result for x = 1 and y = 3.
                                                3
                                     3
                                  9        11
                                    7       10    
        Solution:      We have,   −   xy   ×   xy 3 
                                        3
                                    9        11   
                           7 10
                       =             × (x  × x × y × y ) =  −  70   × x 3 + 1  × y 1 + 3  =  −  70  x y
                                                    3
                                        3
                                                                                   4 4


                           9    11                        99                   99
          Verification:  For x = 1 and y = 3
                                 7

                       LHS =        xy     10  xy 3                                       RHS =  −  70  xy 4
                                     3

                                                                                      4

                                 9          11                                   99

                                 7

                               =      1 3    3    10     13                      =     70   1 4    3  =     70    81  =  −  630
                                                                                           4
                                                        3



                                 9             11                                99                99         11
                                 21
                               =        270       =  −  630


                                   9     11       11
                                                          Thus,  LHS = RHS
        Example 4:  Find the product of 2x y and (3x  + y ).
                                                     3
                                            2
                                                          2
        Solution:      We have, 2x y × (3x  + y ) = (2x y × 3x ) + (2x y × y ) = 6x y + 2x y
                                                                                     2 3
                                                     2
                                              2
                                                                   2
                                                            3
                                                                        2
                                                                               5
                                          3
                                  2

                                                  1
        Example 5:  Multiply  5x      2  x y 4      by  xy  and verify the result for x = 1 and y = 2.
                                                     2
                                         3

                                      3           3

                                                          2
                                                                            2
                                           2
                                                                                   5
        Solution:        5x    2  x y 4      1  x y  =  5x    1 x y    2 x y    1 x y  =  xy −  2  xy  5

                                                                                             5
                                                                                      3
                                3
                                                                    3
                                                                      4






                             3          3              3         3       3         3       9
          Verification:  For x = 1, y = 2

                                                   2
                                                                                     5
                       LHS =  5x     2  x y 4      1  x y                                and RHS =  xy −  2  xy 5

                                                                                               5
                                                                                        3
                                        3



                                     3          3                                    3      9


                                                                            5
                               =  51    2    1    2 4      1    1   2                    =    1      2    1    2  =  10  −  64   = −  34

                                                                                3
                                                                                               5
                                                                                           5
                                           3
                                                         2


                                                                                   2

                                       3              3                     3          9            3    9       9
                                    32             17            34
                                                         2
                                           2

                               =  5            =              =  −


                                     3               3            9
                                                         3
                                           3
                                                              Thus,  LHS = RHS
                                                    Exercise 5.2
          1.  Multiply the following.
             (i)  11x y and 2x y     (ii)  3y  and 7y        (iii) 5x  and 4x        (iv) – 9xy and 4x z
                                                                                                     2
                                                   5
                    2
                            2 2
                                            2
                                                                           9
                                                                    3
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