Page 94 - Mathematics Class - X
P. 94

PROJECT  7






        AIM
        To prove Pythagoras theorem (by method other than given in textbook).


        MATERIALS REQUIRED


               A piece of cardboard
               Two sheets of white paper

               A pair of scissors

        PROCEDURE
        Step 1:  Paste a sheet of white paper on the cardboard.

                 On this paper, draw a right-angled triangle ABC, right angled at C. Let the lengths of the sides AB, BC
                 and CA be c, a and b units respectively (Fig. (a)).                                              A


                                                                                                       c
                                                                                                                   b


                                                                                           B           a          C
                                                                                                     Fig. (a)

        Step 2:  Calculate (a – b). On the other paper, draw a square with each side measuring (a – b) units. Also, draw
                 a square with each side measuring c units.
        Step 3:  Make four exact copies of the ∆ABC on the second paper.
        Step 4:  Cut the two squares and the four triangles from the second paper.                        a – b
        Step 5:  Arrange the square with each side measuring (a – b) units, along with four triangles,
                 as shown in Fig. (b) Place this arrangement over the square of side c units.
                                                                                                          Fig. (b)
        CALCULATIONS
        Area of the square with each side measuring c units = area of the square with each side measuring (a – b)
                                                                    units + 4 (area of the ∆ABC)

                                1
        i.e.,    c  = (a – b)  + 4 (  × a × b)
                          2
                 2
                                2
        ⇒       c  = (a  + b  – 2ab) + 2ab
                          2
                 2
                      2
        ⇒       c  = a  + b
                 2
                          2
                     2
        In other words, the square of the hypotenuse of the right-angled ∆ABC is equal to the sum of the squares of
        the other two sides.
        RESULT
        Pythagoras theorem is verified.


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