Page 82 - Revised Maths Wisdom Class - 6

80 MATHS

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Now, we add the fractional parts, i.e., + Let us subtract 1 from 5
2 3 8 4
32 5 We subtract the whole part i.e., 5 – 1 = 4
=
3
6 6 Now we subtract the fractional part i.e., - 1
5 23 4 8
Hence, the required sum is 3 or 61− 5
6 6 = =
8 8
3 1 5 37
Hence, 5 − 1 = 4 or .
4 8 8 8

ILLUSTRATIONS

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Example 1: Find the sum: + Example 2: Subtract: 1 from 2
4 8 7 5
1 1 21+ 3 3 10 1 11
Solution: + = = Solution: 1 = and 2 =
4 8 8 8 7 7 5 5

11 10 ( 11 7× ) ( 105× ) 77 50− 27
−
⇒ − = = =
5 7 35 35 35
1 4 1 1 2 1
Example 3: Simplify: 1 + 3 − 2 Example 4: Evaluate: + +
3 7 3 7 5 3

1 4 1 4 25 7 1 2 1
Solution: 1 + 3 − 2 = + − Solution: + +
3 7 3 3 7 3 7 5 3

(47× ) (25 3+ × ) (7 7− × ) LCM of 7, 5 and 3 is 105
=
21 (115× ) (2 21+ × ) (135+ × )

28 75 49+ − 103 49− 54 54 3÷ 18 4 = 105
= = = = = = 2
21 21 21 21 3÷ 7 7 15 42 35+ + 92
= 105 = 105 .

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Example 5: Mohit spent of an hour in doing his homework and of an hour in helping his mother. How
3
6
much time did he spend in all?
1
Solution: Time spent in doing homework = of an hour
3
1
Time spent in helping mother = of an hour
6
1 1 21+ 3 1
Total Time spent = + = = = hour
3 6 6 6 2
Example 6: Dimple has 6 erasers. She gave one to her friend and 2 to her brother. She keeps the rest. What
fraction did each of them get? What fraction of her erasers did she give away?

Solution: Total number of erasers Dimple has = 6

Fraction given to her brother = 2 = 1
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