Page 119 - Physics - XI
P. 119

rate of cooling,                             dQ    ms  d       (     )
                                           dt       dt          0
                                            d                     d       k
          or                             ms        k    (  )   or            (      )                          …(1)
                                            dt            0       dt     ms       0

          where k is the constant of proportionality.
                                  dθ   =  –K (θ – θ )                                                          …(2)
                                  dt       1      0
                                                                         k
          As m and s are also constants for the given body, hence  K =  ms   is another constant.
                                                                    1
          Equation (2) can be written as
                                d     =  –K dt                                                                 …(3)

                                    0      1
          Now, on integrating the equation (3) on both sides we have
                                d

                                      =   Kdt
                                            1
                                    0
                          log (θ – θ ) =  – K t + C                                                            …(4)
                                            1
                                    0
          where C is the constant of integration.

          If we plot a graph between log (θ – θ ) and t, it will be a straight line. This is verifi ed from equation (4).
                                                0
          One should keep in mind that Newton's law of cooling holds good for the temperature diff erence between
          the body and its surroundings should not be more than 30°C. Hence, (θ – θ ) should not be more than 30°C.
                                                                                    0
          Procedure

          1.  Clean the Newton's law of cooling apparatus and fi ll the space between its two walls with water which
              acts as surroundings at constant temperature θ .
                                                             0
          2.  Take two thermometers and compare them by measuring the temperature of the same water contained
              in a beaker by both thermometers. Consider one of them, say A, to be the standard thermometer. Find
              the correction to be applied to the other, say B. Suspend thermometer B in water contained in the
              double-walled enclosure as shown in Fig. 6.1.
                                                                                                              3
          3.  Heat water in a beaker to a temperature of about 40°C above the room temperature and fi ll        th of
                                                                                                             4
              calorimeter C with this hot water. Place the lid and stirrer S in proper position and suspend thermometer
              A in hot water in the calorimeter as shown in Fig. 6.1.

          4.  Note the temperature of water in double walled vessel with the help of thermometer B when the
              diff erence of readings on the two thermometers is about 30°C.

          5.  Note the reading of thermometer A and simultaneously start the stopwatch. Gently stir the hot water
              and note the reading of thermometer A after every one minute. After about 5 readings, increase the time
              interval between successive readings to two minutes.
          6.  Keep on taking the readings of thermometer A till the temperature of hot water is about 5°C above the
              room temperature.

          7.  Again note the temperature of water in double-walled vessel with thermometer B and fi nd the mean
              temperature θ  of this water.
                            0
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