Page 49 - Maths Skills - 7

Simple Equations 47

(iii) 9t = 126 (iv) 2m + 6 = 12
Dividing both sides by 9 Subtracting 6 from both sides

9 t 9 = 126 2m + 6 – 6 = 12 – 6
9
⇒ t = 14 ⇒ 2m = 6

Hence, t = 14 is the solution Dividing both sides by 2
of the given equation. 2 m 6
⇒ 2 = 2
⇒ m = 3
Hence, m = 3 is the solution of the given equation.
Example 2: Solve the following equations and verify your answer.

q 10
(i) = (ii) 4a – 7 = 3
5 15

q 10 10
Solution: (i) = Verify: q =
5 15 3
q 10
Multiplying both sides by 5 LHS = = ÷ 5
5 3
q 10 10 × 1
5 × 5 = 15 × 5 = 3 5
10 1 10
⇒ q = = 3 =
3 3 15
10 10
Hence, q = is the solution. RHS =
3 15

Since, LHS = RHS
Hence, verified

5
(ii) 4a – 7 = 3 Verify: a =
2
2 5
Adding 7 to both sides LHS = 4a – 7 = 4 × – 7
2
4a – 7 + 7 = 3 + 7 = 10 – 7

⇒ 4a = 10 = 3
Dividing both sides by 4 RHS = 3
4a 10

4 = 4 Since, LHS = RHS
10 5
⇒ a = = Hence, verified
4 2
5
Hence, a = is the solution.
2