Page 30 - Maths Skills - 7
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28                                                                                                  Maths

          4.  Associative law of multiplication: Multiplication of fractions is associative, i.e. three or more fractions can
            be multiplied in any order.

                              1   2   3   1   6     6     3         1  2  3    2   3    6     3
                                                                                     ×=
                                ×
                                                                           
                                  
            For example;      4   7  × 8   =  4  ×  56  =  224  =  112  and     4  ×  7  ×=  28 8  2224  =  112
                                                                              8
                                  1   2 3    1 2    3
                                             =
                              So,   ×   ×      ×   ×
                                  4   7 8    4 7    8
        RECIPROCAL OF A FRACTION
        A fraction is said to be a reciprocal of a given fraction if their product is 1.

                       2                    3     2   3
        For example;      is the reciprocal of   as,   ×   = 1                       Fact-o-meter
                       3                    2     3   2
                                                                                    Reciprocal is also referred
                                    1      15    7
        Similarly, the reciprocal of 2   or      is                               to as multiplicative inverse
                                    7       7    15
                                   1    15         15     7
                              Q     2  =     and       ×     = 1
                                   7    7           7    15


              Let’s Attempt

                                          15                                                        2   2       1
        Example 1:  Find the product of       and 32.             Example 2:  Find the product of  ,  1  and 2   ·
                                          16                                                        5   3       4
                                      15           15                                          2   2        1
        Solution:      The product of     and 32 =    × 32  2     Solution:     The product of  , 1 , and 2  is
                                      16           16                                          5   3        4

                                                   15 2×                           2   5   9  3  3    1
                                                                      =    = 30  =   ×   ×    =    =  1
                                                     1                             5   3   4  2  2    2


                            5                                                   3
        Example 3:  Find   of 2 hours.                      Example 4:  Find       of 2 hours 40 minutes.
                            6                                                   4
        Solution:      (2 hours ÷ 6) × 5                    Solution:      3   of 2 hours 40 minutes

                       = (120 minutes ÷ 6) × 5                             4  3
                                                                          =     × 2 hours 40 minutes
                       [Q 1 hour = 60 minutes]                               4
                                                                             3
                       = 20 minutes × 5 = 100 minutes                     =     × 160 minutes    [Q 1 hour = 60 min]
                                                                             4
                       = 1 hour 40 minutes.                               = 120 minutes = 2 hours


                                                                                                   3
        Example 5:  A car runs 21 km using 1 litre of diesel. How much distance will it cover using 5  litres of diesel?
                                                                                                   7
        Solution:      Distance covered by the car using 1 litre of diesel = 21 km
                                                          3
                       Distance covered by the car using 5  litres of diesel
                                                          7
                                              3
                                     = 21 5×
                                              7
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