Page 61 - Revised Maths Wisdom Class - 6
P. 61

Number Play                                                                                               59

        Now understand the above concept by using the example given below.
        Take a 4-digit number 9264
        Now,                                      P  = 9642 (biggest number by using digits 9, 2, 6, 4)

                                                 Q  = 2469 (smallest number by using digits 9, 2, 6, 4)
                                                 R  = P – Q = 9642 – 2469
                                                 R  = 7173
        Here                                     R  ≠ 6174

        So, again repeat this concept
        Now taking 4-digit number is 7173
        Here,                                     P  = 7731
                                                 Q  = 1377

                                                 R  = P – Q = 7731 – 1377 = 6354
                                                 R  ≠ 6174
        So, again repeat this concept
        Now, taking 4-digit number is 6354

        Here,                                     P  = 6543
                                                 Q  = 3456
                                         R = P – Q  = 6543 – 3456 = 3087
                                                 R  ≠ 6174

        So, again repeat this concept                                   So, again repeat this concept

        Now, taking 4-digit number is 3087                              Now, taking 4-digit number is 8352
                    P  = 8730                                           Here,      P  = 8532
                    Q  = 0378                                                      Q  = 2358

                    R  = 8730 – 0378 = 8352                                        R  = P – Q = 8532 – 2358 = 6174
                    R  ≠ 6174                                           Here, process completed.


        The Collatz Conjecture (An Unsolved Mystery)
        In 1937, The German Mathematician Lothar Collatz conjectured that the sequence will always reach 1, regardless
        the whole number you start with.
        According to this conjecture, a sequence is prepared by the rule that one starts with any number. It the number is
        even then take half of it and go ahead. But the number is odd then multiply that odd number by 3 and add 1 into
        it and again repeat the above process.

        Let’s understand the above concept with the help of following sequence
              (a)         Even number       Even number          Odd number              Even
                      12                 6                 3                     10                5
                               ÷ 2               ÷ 2            3 × 3 + 1= 10            ÷ 2

                                                        Even        Even        Even        Odd
                                                   2           4           8          16
                   Randomly                             ÷ 2         ÷ 2         ÷ 2        5 × 3 + 1
                   choosen           ÷ 2  Even
                                                1
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