Page 66 - Physics - XI
P. 66

Q32.  In an experiment to study the relation between force of limiting friction and normal reaction,
                     a body just starts sliding on applying a force of 3 N. What will be the magnitude of the force
                     of friction acting on the body when the applied forces on it are 0.5 N, 1.0 N, 2.5 N, and 3.5 N,
                     respectively?                                                                              (NCERT)
              Ans.  Given that a body just starts sliding on applying a force of 3 N. So, it is the limiting friction force. It
                     means if we apply a force less than this force, then the body will not slide. When the applied force
                     on the body is 0.5 N, the magnitude of the force of friction will also be 0.5 N. When the applied
                     force on the body is 1.0 N, the magnitude of the force of friction will also be 1.0 N. When the
                     applied force on the body is 2.5 N, the magnitude of the force of friction will also be 2.5 N. When
                     the applied force on the body is 3.5 N, the magnitude of the force of friction will be 3 N.



                                                       EXPERIMENT - 10

              Aim
              To fi nd the downward force, along an inclined plane, acting on a roller due to gravitational pull of the earth
              and study its relationship with the angle of inclination θ by plotting graph between force and sin θ.


              Apparatus and Materials Required
                An inclined plane with protractor and pulley, roller, pan, weight box, spring balance, strong thread, half
              metre rod, and spirit level

              Principle/Theory

              Inclined plane
              An inclined plane is one of the simplest machine which is used for raising heavy loads by applying less
              eff ort.                                                                       R

              Motion of a roller down an inclined plane                                              Roller  Pulley
              A  roller  of  mass m be put over a smooth inclined plane
              inclined  at  an angle  θ  to  the  horizontal.  The  weight  mg
              of  the  roller  acts  vertically  downwards  (Fig.  10.1).  The                    θ                Pan
              weight  can  be  resolved  into  two  rectangular  components.      mg sin θ
              The  component  mg  cos θ  acting  normally  downwards  on                       mg   mg cos θ     Weight
              the  inclined  plane  and  is  balanced  by  the  upward  normal         θ
              reaction R of the inclined plane. Component mg sin θ of the
              weight acting parallel to the inclined plane downwards and                          Inclined plane
              produces motion in the roller.                                     Fig. 10.1:  Motion of a roller down an

              Let the roller be tied to a thread on the upward direction and                inclined plane
              the thread passes over a frictionless pulley at the top of the inclined plane. Let a pan with some weights be
              tied to the lower free end of the thread.
              A total weight W = Mg which equals to mg sin θ will keep the roller balanced in its position on the inclined
              plane. If there is no friction between inclined plane and the roller, a slightly greater weight will make the
              roller move up the plane and a slightly lesser weight will make the roller move down the plane. Thus, one
              can determine the downward force acting on the roller kept on the inclined plane. The change in the value
              of this force with change of angle can also be studied.


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