Page 19 - Maths Skills - 7
P. 19

Integers                                                                                                17

          6.  In a class test containing 20 questions, 6 marks are awarded for every correct and (–2) are awarded for
            every incorrect answer and 0 for answer not attempted.
             (i)  Astha gets 9 correct answers and 11 incorrect answers. Find her score.
            (ii)   Siddhi scored 36 marks though she got 8 correct answers. How many questions did she attempt
                incorrectly?

        ORDER OF OPERATIONS AND USE OF BRACKETS
        So far we have learnt the basic fundamental operations of addition, subtraction, multiplication and division.
        Mathematical expressions having only one operation can be simplified starting from left to right as shown:
        5 + 7 + 6 + 10 = 28  or  2 × 3 × 4 × 5 = 120
        When we have many operations to be performed then simplifying as we did in the above examples can be quiet
        confusing and may give wrong results. For example, does 24 ÷ 6 × 2 mean ( 24 ÷ 6) × 2 = 4 × 2 = 8 or
        24 ÷ (6 × 2) = 24 ÷ 12 = 2? In such a situation we need to use B O D M A S rule.
          B  → BRACKETS                    O  → OF OR MULTIPLICATION                  D  → DIVISION

         M  → MULTIPLICATION               A  → ADDITION                               S  → SUBTRACTION

        BODMAS denotes the order of operations to be performed. According to it, first the brackets are solved, then 'of'
        followed by the four operations of division, multiplication, addition and subtraction. The operations cannot be
        performed in the order in which they appear in an expression. The order of operation is therefore

        Brackets  → Of (multiplication) →  Division →  Multiplication →  Addition →  Subtraction
        A mathematical expression with brackets is solved in the order:
            Vinculum                  Braces

               ‘—’     ⇒      (  )     ⇒     {  }     ⇒     [  ]

                        Parentheses          Square Brackets


              Let’s Attempt


        Example 1:  Simplify.
                        (i) 10 – (5 + 3 – 2)             (ii)  15 – (– 3) × (5) + 10
        Solution:      (i)  10 – (5 + 3 – 2) = 10 – 6 = 4    (ii)  15 – (– 3) × (5) + 10 = 15 – (– 15) + 10 = 15 + 15 + 10 = 40

        Example 2:  Simplify.

                       (i)  18 ÷ (8 – 4 + 2)                          (ii)  36 – [15 – {9 ÷ (17 + 3 × 2 – 20)}]
        Solution:      (i)  18 ÷ (8 – 4 + 2)                  [Removing Vinculum]
                           = 18 ÷ (8 – 6)                     [Removing Parentheses]

                                        = 18 ÷ 2 = 9
                       (ii)  36 – [15 – {9 ÷ (17 + 3 × 2 – 20)}]

                            = 36 – [15 – {9 ÷ (17 + 6 – 20)}]
                            = 36 – [15 – {9 ÷ (23 – 20)}]           [Removing Parentheses]
                            = 36 – [15 – {9 ÷ 3}]                   [Removing Braces]
                            = 36 – [15 – 3]                         [Removing Square Brackets]

                            = 36 – 12 = 24
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