Page 50 - Hindi - 5

Kku >jks[kk
Kku >jks[kk
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iz'kkar egklkxj esa lcls vf/d rwiQku vkrs gSaA rwiQkuksa dh oqQy la[;k esa fgan egklkxj nwljs vkSj vVykafVd
egklkxj rhljs LFkku ij gSA

O;kogkfjd O;kdj.k
O;kogkfjd O;kdj.k (Functional Grammar)

tks 'kCn laKk osQ LFkku ij iz;ksx fd, tkrs gSa] os loZuke dgykrs gSa_ tSlsµ;g] og] eSa]
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mls vkfnA

1- uhps fn, x, okD;ksa esa ls loZuke 'kCn pqudj fyf[k,µ

(d) mls vius ns'k dh ;kn lrkus yxhA ------------------------------------------
([k) mlosQ laosQr ij tgk”k pyus yxkA ------------------------------------------

(x) og fyyhiqV ij p<+kbZ djuk pkgrk FkkA ------------------------------------------

(?k) mu fofp=k izkf.k;ksa us rhj pykuk can dj fn;kA ------------------------------------------
(Ä) mls ,d xkM+h esa j[kdj dgha ys tk jgs FksA ------------------------------------------

oqQN 'kCnksa osQ var esa 'kCnka'k yxkdj ge u, 'kCn cuk ldrs gSaA bu 'kCnka'kksa dks izR;;
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dgrs gSa_ tSlsµ Hkkjr + bZ; = Hkkjrh;] lqanj + rk = laqnjrk vkfnA

2- uhps fn, x, 'kCnksa esa izR;; tksM+dj 'kCn cukb,µ
(d) eèkqj + rk = ---------------------- ([k) tho + br = ----------------------

(x) LFkku + b; = ---------------------- (?k) ,d=k + br = ----------------------

(Ä) jk"Vª + bZ; = ---------------------- (p) dBksj + rk = ----------------------
(N) iM+ksl + bZ = ---------------------- (t) vkuan + br = ----------------------

vuqLokj% ^mQ* dk mPpkj.k ukd ls gksrk gSA bls vuqLokj dgrs gSaA bls o.kZ osQ mQij (a)
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n~okjk n'kkZ;k tkrk gS_ tSlsµ vax] vaxwj vkfnA

vuqukfld% o.kZ osQ mQij yxus okys paæfcanq ( ¡) dks vuqukfld dgrs gSaA bldk mPpkj.k
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ukd vkSj xys ls gksrk gS_ xk¡o] lk¡l vkfnA

3- uhps fn, x, 'kCnksa esa lgh txg ij vuqLokj ( a ) ;k vuqukfld ( ¡ ) yxkb,µ

(d) i[kk & ---------------------- ([k) igqpk & ----------------------

(x) losQr & ---------------------- (?k) cklqjh & ----------------------
(Ä) 'k[k & ---------------------- (p) O;tu & ----------------------

(N) vnj & ---------------------- (t) vkoyk & ----------------------

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